2/3x^2-5=x/3

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Solution for 2/3x^2-5=x/3 equation: 


x in (-oo:+oo)

(2/3)*x^2-5 = x/3 // - x/3

(2/3)*x^2-(x/3)-5 = 0

2/3*x^2-1/3*x-5 = 0

DELTA = (-1/3)^2-(-5*2/3*4)

DELTA = 121/9

DELTA > 0

x = ((121/9)^(1/2)+1/3)/(2/3*2) or x = (1/3-(121/9)^(1/2))/(2/3*2)

x = 3 or x = -5/2

x in { -5/2, 3 }

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